Try
(num << 3 - num)
This is same as
num*8 - num = num * (8-1) = num * 7
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13 comments:
The first answer is not completely accurate
(num << 3 - num)
Due to order of operations you will get some erroneous data
The corrected format should be
(num << 3)- num
it's interesting that you can do it with every (2^x)-1 number - 3, 7, 15, 31...
<< precede - so num<<3-num is fine though it is better to do (num << 3) - num for readability.
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