Saturday, July 7, 2007

Write your own strcat() function.

Here is a C function which implements the strcat() function...


/* Function to concatenate string t to end of s; return s */
char *myStrcat(char *s, const char *t)
{
char *p = s;

if (s == NULL || t == NULL)
return s; /* we need not have to do anything */

while (*s)
s++;

while (*s++ = *t++)
;

return p;
}

15 comments:

Anonymous said...

this will cause access violation
since you don't know what's after s++ it might be something else on the stack

jimmy said...

for example ,when char *s is "1920219",inside of the string, there is a "0". when you use while(*s),the loop will interrupt. So I cannot sure the program will work well.

soumyadip said...

if we write
while(*s!='/0')

instead of
while(*s)

tada..problem solved!!

Anonymous said...

No. Zero has a value of 48 since it is ASCII. The loop will not break unless it specifically a '/0' which is 0 in ASCII.

Unknown said...

it is not working

Unknown said...

it is not working

Anonymous said...

char* myStrcat(char *s, const char *t)
{
char *p = s;

if (s == NULL || t == NULL)
return s; /* we need not have to do anything */

while ((*s) != '\0')
{
s++;
}

while ((*t) != '\0')
{
*s++ = *t++;
}

*s = '\0';

return p;
}

Anonymous said...

Make sure parameter 's' has enough space to hold both strings.

For example:
char dest[100] = "test ";
char src[] = "this out";
myStrcat(dest, src);

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