Monday, July 9, 2007

Write a program to add two long positive numbers (each represented by linked lists).

Check out this simple implementation


mynode *long_add(mynode *h1, mynode *h2, mynode *h3)
{
mynode *c, *c1, *c2;
int sum, carry, digit;

carry = 0;
c1 = h1->next;
c2 = h2->next;

while(c1 != h1 && c2 != h2)
{
sum = c1->value + c2->value + carry;
digit = sum % 10;
carry = sum / 10;

h3 = insertNode(digit, h3);

c1 = c1->next;
c2 = c2->next;
}

if(c1 != h1)
{
c = c1;
h = h1;
}
else
{
c = c2;
h = h2;
}

while(c != h)
{
sum = c->value + carry;
digit = sum % 10;
carry = sum / 10;
h3 = insertNode(digit, h3);
c = c->next;
}

if(carry==1)
{
h3 = insertNode(carry, h3);
}

return(h3);
}

11 comments:

Kevin said...

I may be missing something but how will the first loop ever terminate since h1 and h2 never change and c1 and c2 will hit the end of their lists.

Amar Sharma said...

Mysterious operations in the program.
Unable to understand the logic - please throw more light.

subha said...

the code is not understandable..is this code for a circularly linked list??please provide some explanation..

shitu said...

please provide some explenation

sandeep kumar said...

Thanks for the info. It is very helpful.
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