Check out this simple implementation

mynode *long_add(mynode *h1, mynode *h2, mynode *h3)

{

mynode *c, *c1, *c2;

int sum, carry, digit;

carry = 0;

c1 = h1->next;

c2 = h2->next;

while(c1 != h1 && c2 != h2)

{

sum = c1->value + c2->value + carry;

digit = sum % 10;

carry = sum / 10;

h3 = insertNode(digit, h3);

c1 = c1->next;

c2 = c2->next;

}

if(c1 != h1)

{

c = c1;

h = h1;

}

else

{

c = c2;

h = h2;

}

while(c != h)

{

sum = c->value + carry;

digit = sum % 10;

carry = sum / 10;

h3 = insertNode(digit, h3);

c = c->next;

}

if(carry==1)

{

h3 = insertNode(carry, h3);

}

return(h3);

}

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## 11 comments:

I may be missing something but how will the first loop ever terminate since h1 and h2 never change and c1 and c2 will hit the end of their lists.

Mysterious operations in the program.

Unable to understand the logic - please throw more light.

the code is not understandable..is this code for a circularly linked list??please provide some explanation..

please provide some explenation

Thanks for the info. It is very helpful.

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