Try something like this
# include < stdio.h >
void main()
{
int num=123456;
int sum=0;
for(;num > 0;sum+=num%10,num/=10); // This is the "single line".
printf("\nsum = [%d]\n", sum);
}
If there is a simpler way to do this, let me know!
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6 comments:
The number of expressions is far more interesting than the number of statments. In the example code you have at least 3 expressions in the one for statment (which you also call 'single line').
you could do something like
do { sum += num % 10} while (num /= 10);
instead, which is better for most compilers, is also a single line, has one less expression in it (doesn't have num > 0) and doesn't reject negative numbers.
u r awesome :)doing a great job
nice post Interview Questions
void sumdigit(int n) //single line
{
int s = 0;
while((s=s+(n%10))&&(n=n/10)>0)
;
printf("\nSum of Difit : %d",s);
}
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