Write a C program to implement a Generic Linked List.
Here is a C program which implements a generic linked list. This is also one of the very popular interview questions thrown around. The crux of the solution is to use the void C pointer to make it generic. Also notice how we use function pointers to pass the address of different functions to print the different generic data.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct list {
void *data;
struct list *next;
} List;
struct check {
int i;
char c;
double d;
} chk[] = { { 1, 'a', 1.1 },
{ 2, 'b', 2.2 },
{ 3, 'c', 3.3 } };
void insert(List **, void *, unsigned int);
void print(List *, void (*)(void *));
void printstr(void *);
void printint(void *);
void printchar(void *);
void printcomp(void *);
List *list1, *list2, *list3, *list4;
int main(void)
{
char c[] = { 'a', 'b', 'c', 'd' };
int i[] = { 1, 2, 3, 4 };
char *str[] = { "hello1", "hello2", "hello3", "hello4" };
list1 = list2 = list3 = list4 = NULL;
insert(&list1, &c[0], sizeof(char));
insert(&list1, &c[1], sizeof(char));
insert(&list1, &c[2], sizeof(char));
insert(&list1, &c[3], sizeof(char));
insert(&list2, &i[0], sizeof(int));
insert(&list2, &i[1], sizeof(int));
insert(&list2, &i[2], sizeof(int));
insert(&list2, &i[3], sizeof(int));
insert(&list3, str[0], strlen(str[0])+1);
insert(&list3, str[1], strlen(str[0])+1);
insert(&list3, str[2], strlen(str[0])+1);
insert(&list3, str[3], strlen(str[0])+1);
insert(&list4, &chk[0], sizeof chk[0]);
insert(&list4, &chk[1], sizeof chk[1]);
insert(&list4, &chk[2], sizeof chk[2]);
printf("Printing characters:");
print(list1, printchar);
printf(" : done\n\n");
printf("Printing integers:");
print(list2, printint);
printf(" : done\n\n");
printf("Printing strings:");
print(list3, printstr);
printf(" : done\n\n");
printf("Printing composite:");
print(list4, printcomp);
printf(" : done\n");
return 0;
}
void insert(List **p, void *data, unsigned int n)
{
List *temp;
int i;
/* Error check is ignored */
temp = malloc(sizeof(List));
temp->data = malloc(n);
for (i = 0; i < n; i++)
*(char *)(temp->data + i) = *(char *)(data + i);
temp->next = *p;
*p = temp;
}
void print(List *p, void (*f)(void *))
{
while (p)
{
(*f)(p->data);
p = p->next;
}
}
void printstr(void *str)
{
printf(" \"%s\"", (char *)str);
}
void printint(void *n)
{
printf(" %d", *(int *)n);
}
void printchar(void *c)
{
printf(" %c", *(char *)c);
}
void printcomp(void *comp)
{
struct check temp = *(struct check *)comp;
printf(" '%d:%c:%f", temp.i, temp.c, temp.d);
}
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8 comments:
Hi, I see this is very useful for me,
Here i receive one compile error in the below line
*(char *)(temp->data + i) = *(char *)(data + i);
error is:
"error C2036: 'void *' : unknown size"
I have corrected this by placing typecast near to temp->data as below:
*((char *)temp->data + i) = *((char *)data + i);
Pls confirm whether I overlook any.
Thanks.
Thirumalai
minor: string insertion takes the size as str[0] for all of the strings.
hello vijay!u r copying every thing frm internet dnt do this k..nothing is correct in ur blog..dnt make copy and paste..k.be care
hello vijay!u r copying every thing frm internet dnt do this k..nothing is correct in ur blog..dnt make copy and paste..k.be care.............website ex:http://profile.iiita.ac.in/pkmallick_03/pages/0_4.html
i think even templates can be used to create a generic link list:):)
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