Here is a simple C program to accomplish the same.
int compare_linked_lists(struct node *q, struct node *r)
{
static int flag;
if((q==NULL ) && (r==NULL))
{
flag=1;
}
else
{
if(q==NULL || r==NULL)
{
flag=0;
}
if(q->data!=r->data)
{
flag=0;
}
else
{
compare_linked_lists(q->link,r->link);
}
}
return(flag);
}
Another way is to do it on similar lines as strcmp() compares two strings, character by character (here each node is like a character).
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33 comments:
hey.. keep up d good work in dis blog :) by d way.. i ve a more compact recursive soln.. plz tell me if u find any bug..
int comp(struct node *p,struct node *q)
{
if(!p&&!q)
return 1;
if((!p&&q)||(!q&&p))
return 0;
return((p->info==q->info)&&(comp(p->link,q->link)));
}
Lol,
Me
Hi,
Gud job dude.
I have a doubt that this function would work in all conditions.
check the else part
else
{
if(q==NULL || r==NULL)
{
flag=0;
}
if(q->data!=r->data)
{
flag=0;
}
when q is NULL but r is not NULL it will come to the above else part. then it will check the first if condition and make the flag 0
now it will come to the second if condition and try to access the q->data. here q is NULL and it is trying to accesses q->data so it will crash.
Please pardon me if i was wrong somewhere.
Thanks and Regards,
Sandy
More Compact
int comp(struct node *p,struct node *q)
{
if(!p&&!q)
return 1;
if((!p)||(!q)) /*LOL*/
return 0;
return((p->info==q->info)&&(comp(p->link,q->link)));
}
Thanks a lot!!Good job!! It is a very good collection!!
Bool Compare(Node *a, Node* b) {
If (a== NULL && b== NULL) {
Return 0;
} else if (a== NULL) {
return -1;
} else if (b == NULL) {
return 1;
}
while (a != NULL && b!= NULL) {
lastCompare = compare(a.data, b.data);
if (lastCompare != 0) {
return lastCompare;
}
A = a->next;
B = b->next;
}
if (a== NULL && b== NULL) {
Return lastCompare;
} else if (a== NULL) {
return -1;
} else if (b == NULL) {
return 1;
}
}
if(q==NULL || r==NULL)
{
flag=0;
return(flag); -->[to avoid crash when
either q or r is NULL]
}
Please correct if i am wrong
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