#include < stdio.h >
char *trim(char *s);
int main(int argc, char *argv[])
{
char str1[]=" Hello I am Good ";
printf("\n\nBefore trimming : [%s]", str1);
printf("\n\nAfter trimming : [%s]", trim(str1));
getch();
}
// The trim() function...
char *trim(char *s)
{
char *p, *ps;
for (ps = p = s; *s != '\0'; s++)
{
if (!isspace(*s))
{
*p++ = *s;
}
}
*p = '\0';
return(ps);
}
And here is the output...
Before trimming : [ Hello I am Good ]
After trimming : [HelloIamGood]
Another version of this question requires one to reduce multiple spaces, tabs etc to single spaces...
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7 comments:
cnt we do this without using pointers?
can u just tell how to remove the beginning and end white spaces alone
char *trim_string(char *str)
{
int i=0,j=0;
while(str[j] != '\0')
{
if(str[j] == ' ')
j++;
str[i++]=str[j++];
}
str[i]='\0';
return &str;
}
Thanks for the info. It is very helpful.
Regards
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